如何将参数传递给python中的timeit function？

Question

import timeit
#those are the parameters that need to be passed
list1=["Ahmed","Ahmedd"]
#loop through the parameters
for x in list1:
mysetup=x
#the function to be tested 
mycode='''
#testing if the string is unique
def is_unique_chars_using_set(string):
#Solution Using Set
characters_seen = set()
for char in string:
    if char in characters_seen:
        return False
    characters_seen.add(char)
return True'''
print (timeit.timeit(stmt = mycode,number = 1000000))

如何将这些参数传递给timeit ？

Answer 1

这里的代码实际上并没有使用列表。 timeit 无法查看循环内部。 （即它应该在适当的范围内）

下面的代码将为您工作

import timeit
#those are the parameters that need to be passed
list1=["Ahmed","Ahmedd"]
#loop through the parameters

#the function to be tested 
mycode='''
#testing if the string is unique
def is_unique_chars_using_set(string):
    #Solution Using Set
    characters_seen = set()
    for char in string:
        if char in characters_seen:
            return False
        characters_seen.add(char)
    return True'''
print (timeit.timeit(stmt = mycode,number = 1000000))

如果需要 for 循环，那么您需要在“我的代码”中包含 for 循环

import timeit
mycode='''
list1=["Ahmed","Ahmedd"]
for x in list1:
    mysetup=x
    #testing if the string is unique
    def is_unique_chars_using_set(string):
        #Solution Using Set
        characters_seen = set()
        for char in string:
            if char in characters_seen:
                return False
            characters_seen.add(char)
        return True'''
print (timeit.timeit(stmt = mycode,number = 1000000))