如何让 function 返回另一个 function

Question

How do I make a function that returns another function, but without an if statement?

For example:

def mainFunction():
    if addRequirement(10) == False: return

def addRequirement(r):
    if r > 0: return True
    else: return False

The above, except without the 'if xyz == False: return' part, just 'addRequirement(10)'

Thanks,

EDIT 1:

I should have mentioned that I'm writing a discord bot, and that the bot's command has a requirement. The addRequirement function just cancels the main async function if it isn't met.

Answer 1

Not sure I fully understand the requirement here but perhaps:

def mainFunction():
    return addRequirement(10)

def addRequirement(r):
    return r > 0

Answer 2

If you mean that you want to write a command to return a value based on a condition without using the 'if' statement, you can use inline if as follows:

def addRequirement(r):
    return something if anyConditions else somethingElse

But, if you mean you just wanna change the main function and the program still works, you can use this:

def mainFunction():
    addRequirement(10)

def addRequirement(r):
    return passFunction if r>0 else retFunction

def passFunction():
    pass

def retFunction():
    return