使用核心 python 将列表中的列相乘，无需任何导入库

Question

If I have the data like this

[['6', '0.24','B','C'], ['6', '0.22','A','C'], ['4', '0.20', 'A','X']]

and now I want to find out max of (6/.24, 6/0.22, 4/0.20) AND finally, which ever has max value, show col values at index 2 and 3. Output I am expecting should look something like this: 27.27273, A, C (A, C are the corresponding values in the list where we found max value) Thanks again.

Answer 1

Sort the list by the difference between first 2 elements

lst = [['6', '0.24','B','C'], ['6', '0.22','A','C'], ['4', '0.20', 'A','X']]
sorted_lst = sorted(lst, key=lambda x: float(x[0])/float(x[1]), reverse=True)
x = sorted_lst[0]
result = [float(x[0])/float(x[1]), x[2], x[3]]
print(result)

Output:

[27.272727272727273, 'A', 'C']

Answer 2

Build a list of the (6/.24, 6/0.22, 4/0.20) values and then take the max.

a = [['6', '0.24','B','C'], ['6', '0.22','A','C'], ['4', '0.20', 'A','X']]

b = max([float(x[0])/float(x[1]) for x in a])
print(b)

Answer 3

def get_maxrow(data):
  x = [[float(i[0])/float(i[1]), *i[2:]] for i in data]
  return max(x)

x = [['6', '0.24','B','C'], ['6', '0.22','A','C'], ['4', '0.20', 'A','X']]

y = get_maxrow(x)
print(y) # [27.272727272727273, 'A', 'C']