使用 RegEx 和 javascript 剪切多行字符串

Question

I have example text:

var text = `class Eee {
   test(){
     console.log("123");
   }
}
use(123, Eee);

class Ttt {
   test(){
     console.log("123");
   }
}
use(456, Ttt);


class Ooo {
   test(){
     console.log("123");
   }
}
use(111, Ooo);
`;

And I wont get part text for example:

`class Ttt {
   test(){
     console.log("123");
   }
}
use(456, Ttt);`

If I use RegEx:

let result = text.match(/^class Ttt \{(.*)/gm); 

I have result: [ 'class ttt {' ]

If I use RegEx:

let result = text.match(/^class Ttt \{(.*)\}/gm); 

or

let result = text.match(/^class Ttt \{(.*)use\([\b].Ttt\);/gm);

I have result: null . How can I get the entire piece of text I want, not the first line?

Answer 1

You specified where the match should start, but you also have to specify where is should end.

If the end for example is at the start of a new line and the next line should be use(456, Ttt); on it's own:

^[^\S\n]*class Ttt {[^]*?\n\s*}\s*\n\s*use\(.*\);$

Note that \s can also match newlines.

The pattern in parts:

• ^ Start of string
• [^\S\n]* Match optional whitespace chars without newlines
• class Ttt { Match literally
• [^]*? Match any character including newlines, as few as possible
• \n\s*}\s* Match a newline and } between optional whitespace chars
• \nuse\(.*\); Match a newline and use(...);
• $ End of string

Regex demo

 var text = `class Eee { test(){ console.log("123"); } } use(123, Eee); class Ttt { test(){ console.log("123"); } } use(456, Ttt); class Ooo { test(){ console.log("123"); } } use(111, Ooo); `; const regex = /^[^\S\n]*class Ttt {[^]*?\n\s*}\s*\n\s*use\(.*\);$/m; const m = text.match(regex); if (m) { console.log(m[0]); }

Answer 2

For what it's worth, here's a non-regex version:

'class ' + text.split('class ')[1]

 var text = `class Eee { test(){ console.log("123"); } } use(123, Eee); class Ttt { test(){ console.log("123"); } } use(456, Ttt); class Ooo { test(){ console.log("123"); } } use(111, Ooo); `; console.log('class ' + text.split('class ')[1])