是否不可能在 JavaScript 中使用多行正则表达式模式指示输入字符串的开头？

Question

In JavaScript, the multiline flag changes the meaning of ^ and $ :

Treat beginning and end characters (^ and $) as working over multiple lines (ie, match the beginning or end of each line (delimited by \\n or \\r), not only the very beginning or end of the whole input string)

Well, with those characters out of the picture, are there any other ways to mark the start of the input string? How can I indicate that I want my multiline pattern to only match at the start of the input string?

I know I can check the index of the match using the index property of the return value of exec , but is there a way to prevent the regex engine from searching the entire string in the first place?

Answer 1

No, ^ is the only built-in assertion that tests for beginning-of-input and, as you said, its behavior is modified by the multiline flag.

You could put some unique string at the beginning of the string you're testing and also at the beginning of your regular expression, but that's a bit of a hack. In the normal case, as you said, you'd test the index of the returned match.

Answer 2

No, JavaScript doesn't support the absolute anchors ( \\A , \\Z and \\z ) like most other flavors do. But are you sure you need them? The beginning of the string is usually the only place where you must use an anchor. Each subsequent line is automatically "anchored" by the newline preceding it.

I suggest you drop the multiline flag and make sure you explicitly consume all the newlines. I know that's kinda vague; if you were to supply a code sample and/or tell us what problem you're trying to solve, we might be able to do better.

Answer 3

In 2021, with the growing adoption of the ECMAScript 2018+ standard that supports the lookbehind construct in a RegExp , you can now use an "absolute", unambiguous start of string position in the multiline mode regex if you use

/^(?<![^])/gm

Although the g flag allows multiple matching and m allows ^ to match any line start position, the ^(?<![^]) pattern only matches

• ^ - start of a line that
• (?<![^]) - has no char immediately to the left of it. [^] matches any char in an ECMAScript regex.

Alternatives :

/^(?<![\w\W])/gm
/^(?<!.)/gsm

where [\\w\\W] matches any chars including line breaks (a synonymic contruct to [\\s\\S] and [\\d\\D] ), and /s flag makes . line break aware.

See the JavaScript demo:

 const regex = /^(?<![^])/gm; // g - multiple matching enabled! const text = 'Line 1\\nLine 2\\nLine 3'; console.log(text.replace(regex, 'INSERTION...')); // Only the first line affected // => INSERTION...Line 1 // Line 2 // Line 3