[英]regular expression to match start character of string + space then digits like currency
How do I test a string that contains a character at the start then a space and whatever comes after that which could be an integer or float?如何测试一个字符串,该字符串在开头包含一个字符,然后是一个空格,然后是 integer 或浮点数?
Example:例子:
'$ 15' '$ 15'
'$ 15.95' '$ 15.95'
/\$\s[\d]*\.[\d]{2}|\$\s[\d]*[^.]/gm
$space(endless digits until)period and exactly-2digits
|OR
$space(endless digits-no periods)
const rgx = /\$\s[\d]*\.[\d]{2}|\$\s[\d]*[^.]/gm; const str = `\$ 15.95 \$ 5 \$ 2.00 \$ 6.90 \$ 1101`; let matches = [...str.matchAll(rgx)].flat(); console.log(matches);
I think it could help you: ^\$ [+-]?[0-9]{1,}(\.[0-9]{1,}){0,1}
, you can test it here: https://regex101.com/我认为它可以帮助你:
^\$ [+-]?[0-9]{1,}(\.[0-9]{1,}){0,1}
,你可以在这里测试它: https ://regex101.com/
^\$
: start with a character ^\$
: 以字符开头[+-]?
then add optional signs[0-9]{1,}
then add at less one digit [0-9]{1,}
然后添加少一位数(\.[0-9]{1,}){0,1}
then add a dot and at less one digit (\.[0-9]{1,}){0,1}
然后添加一个点并且少于一位You can use below regular expression:您可以使用以下正则表达式:
. . \d+(?:.\d+)?
\d+(?:.\d+)?
Test it here: https://regex101.com/r/1oqIO8/1在这里测试: https://regex101.com/r/1oqIO8/1
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