如何从列表中删除符合条件的项目

Question

I am attempting to identify if an item is even and then removing them from any list and printing the new list

def remove_evens(my_list):
    if item in my_list 0 % 2 == 0:
        # how do I remove the specified items?
    return list

Answer 1

Try this:

numbers = [10, 20, 3, 15, 1000, 60, 16]
removed_evens = list(filter(lambda n: n % 2 != 0, numbers))
print(removed_evens)

And function form:

def removed_evens(numbers):
    return list(filter(lambda n: n % 2 != 0, numbers))

Another logic:

def removed_evens(numbers):
    results = []
    for number in numbers:
        if number % 2 != 0:
            results.append(number)
    return results

Which can be reduced to:

def removed_evens(numbers):
    return [number for number in numbers if number % 2 != 0]

Or even more minimal:

removed_evens = lambda numbers: [number for number in numbers if number % 2 != 0]

Answer 2

def remove_evens(my_list):
    for item in my_list:
        if item %2 == 0:
            my_list.remove(item)
    return my_list
my_list = [1,2,3,4,5,6]
remove_evens(my_list)
print(my_list)