[英]Glob files except that including some expression
I want to write a command to build FooMain.cc
among the following files:我想编写一个命令来在以下文件中构建
FooMain.cc
:
$ ls src
FooMain.cc
FooMain2.cc
BarMain.cc
Helper.cc
Helper.h
FileToInclude.cc
FileToInclude.h
...
Each main file (those including Main
) has main()
function and they require all the other files without Main
in filenames.每个主文件(包括
Main
的文件)都有main()
function 并且它们需要文件名中没有Main
的所有其他文件。
The straightforward way to build would be like:构建的直接方法如下:
clang++ [options] FooMain.cc Helper.cc FileToInclude.cc ...
Here the expression HelperOne.cc FileToInclude.cc...
includes all the files but those including Main
.这里的表达式
HelperOne.cc FileToInclude.cc...
包括除Main
之外的所有文件。 What I want to do is rephrase this expression with glob expression我想做的是用 glob 表达式改写这个表达式
clang++ [options] FooMain.cc [Some clever glob expression]
I looked up for a while but could not find similar questions.我查了一会儿,但找不到类似的问题。 Appreciate any clues.
感谢任何线索。 Thank you!
谢谢!
Using ksh93
, bash
with the extglob option turned on ( shopt -s extglob
), or zsh
with the ksh_glob option turned on ( setopt ksh_glob
):使用
ksh93
、 bash
并打开extglob选项 ( shopt -s extglob
),或使用zsh
并打开ksh_glob选项 ( setopt ksh_glob
):
$ clang++ [options] FooMain.cc !(*Main*).cc
Using zsh
with the extended_glob option turned on ( setopt extended_glob
):在启用extended_glob选项的情况下使用
zsh
( setopt extended_glob
):
$ clang++ [options] FooMain.cc *.cc~*Main*
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