REGEX 如何检查一个字符串中是否有超过 2 个空格？

Question

I am trying to regex (ECMAscript) check if a string has three or more spaces in it. Essentially, I want the minimum number of spaces to be 3 before it matches. Here are some examples;

"Microsoft and Apple" This would NOT match

"The quick brown fox" This WOULD match

"lots of spaces in this sentence" This WOULD match

This is the best I have so far;

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/[\s]{3,}/gm

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Answer 1

If the 'string' can contain everything (characters and numbers and special chars):

/^((.*?)? (.*?)?){3,}?$/gm

Answer 2

This may not be optimally efficient, but you could split on spaces and then check the resulting length:

 const x = [ "Microsoft and Apple", "The quick brown fox", "lots of spaces in this sentence", ] x.forEach(s => console.log(s, s.split(' ').length > 3))

Answer 3

Put three spaces in the regex, and match anything else around them

.*.*.*.*

Answer 4

A regex that makes sure there at least 3 whitespaces in a string is

/^(?:\S*\s){3}/

See the regex demo . Details :

• ^ - start of string
• (?:\S*\s){3} - three occurrences of zero or more non-whitespace chars and then a whitespace.

See the JavaScript demo:

 const texts = ['Microsoft and Apple','The quick brown fox','lots of spaces in this sentence']; const re = /^(?:\S*\s){3}/; for (const text of texts) { console.log(text, '=>', re.test(text)); }

Answer 5

The pattern /[\s]{3,}/gm matches 3 continuous whitespace characters, and \s can also match newlines.

Note that you don't need /m as the pattern has no anchors, but you do need /g to get all matches.

You can match all spaces and only get the string that has more than 2 spaces (or if you really want to use \s then use that)

 [ "Microsoft and Apple", "The quick brown fox", "lots of spaces in this sentence" ].forEach(s => { if ((s.match(/ /g) || []).length > 2) { console.log(s); } });