[英]Copy lines from file to char *array[]?
Hi need a little bit of help here.您好这里需要一点帮助。 I have a file with 5 lines and I want to put this lines into an array of type
char *lines[5];
我有一个包含 5 行的文件,我想将这些行放入一个
char *lines[5];
but I can't figure it out why the following isn't working.但我无法弄清楚为什么以下内容不起作用。
#include <stdio.h>
#include <string.h>
int main(void) {
FILE *fp = fopen("name.txt", "r");
char *str;
char *list[5];
int i = 0;
while (fgets(str, 100, fp) != NULL) // read line of text
{
printf("%s", str);
strcpy(list[i], str);
i++;
}
}
As the commenters stated, you need to create an array (which is nothing more than a space in the memory) of a sufficient size to store your string.正如评论者所说,您需要创建一个足够大的数组(只不过是内存中的一个空间)来存储您的字符串。 One approach to solve your problems is the following, note the comments:
解决问题的一种方法如下,请注意注释:
#include <stdio.h>
#include <string.h>
int lines(FILE *file); //try to format the code according to some standard
int main(void) {
FILE *fp = fopen("name.txt", "r");
char list[5][100]; //make sure you allocate enough space for your message
// for loop is more elegant than while loop in this case,
// as you have an index which increases anyway.
// also, you can make sure that files with more than 5 lines
// do not break your program.
for(int i = 0; i<5 ;++i )
{
if(fgets(list[i], 100, fp) == NULL){
break;
}
//list[i] is already a string, you don't need an extra copy
printf("%s", list[i]);
}
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.