Pandas - 如何根据另一列的条件找到 1 列的前 n 个元素

Question

I am struggling with a question based on Pandas. I have an earthquake data set with columns of countries and magnitudes. I am asked to: "Find the top 10 states / countries where the strongest and weakest earthquakes occurred."

From this question, I garnered that I am meant to find the top 10 countries ["country"] with the highest values (value_counts), but sorting by magnitude ["mag"].

How would I go about doing this? I've looked around but there's nothing I've found about this online.

Answer 1

Are you sure you did not find something useful? If I understand your question correct, it is a simple one. After creating a dataframe by using below methods, you will get what you need.

import pandas as pd 
df = pd.read_csv(".csv") 
df.nlargest(x, ['Column Name'])

x is the number of elements which are the largest ones. Same is goes for nsmallest too. Just use these:

DataFrame.nsmallest(n, columns, keep='first')
DataFrame.nlargest(n, columns, keep='first')

Please read and check the documentation first.