从 larave 框架运行 python 脚本

Question

Hi everyone who i can i pass laravel parameter with symfony process code i use it to run python script

use Symfony\Component\Process\Process; 
use Symfony\Component\Process\Exception\ProcessFailedException; 
 
$process = new Process(['python3','/path/to/your_script.py',$policyname); 
$process->run();

Answer 1

yes you can pass laravel parameter to python.

1. You need to install symfony/process using following command:

    composer require symfony/process

2. you can use it in laravel as

   use Symfony\Component\Process\Process; use Symfony\Component\Process\Exception\ProcessFailedException; $process = new Process(['python', '/path/to/script.py']); $process->run(); // error handling if (;$process->isSuccessful()) { throw new ProcessFailedException($process); } $output_data = $process->getOutput();

If you want to pass parameters to python, do this:

$process = new Process(['python', '/path/to/script.py', $arg]);