Plotly单杠比较

Question

The chart attached is from R plotly package. Does this exist or can be done in python using the plotly package?

Answer 1

You can create diverging stacked bars in plotly-python by plotting the bars for male and female populations as separate traces, making the population values negative for the men, and then using the original values in the customdata so the populations for men display positive values.

I followed the method outlined by @empet in his answer here , and modified the categories and hovertemplate to fit your example.

import numpy as np
import pandas as pd
import plotly.graph_objects as go

d = {'Age': ['0-19','20-29','30-39','40-49','50-59','60-Inf'],
     'Male': [1000,2000,4200,5000,3500,1000],
     'Female': [1000,2500,4000,4800,2000,1000],
}
df = pd.DataFrame(d)

fig = go.Figure()
fig.add_trace(go.Bar(x=-df['Male'].values,
                        y=df['Age'],
                        orientation='h',
                        name='Male',
                        customdata=df['Male'],
                        hovertemplate = "Age: %{y}<br>Pop:%{customdata}<br>Gender:Male<extra></extra>"))
fig.add_trace(go.Bar(x= df['Female'],
                        y =df['Age'],
                        orientation='h',
                        name='Female',
                        hovertemplate="Age: %{y}<br>Pop:%{x}<br>Gender:Female<extra></extra>"))    

fig.update_layout(barmode='relative', 
                  height=400, 
                  width=700, 
                  yaxis_autorange='reversed',
                  bargap=0.01,
                  legend_orientation ='h',
                  legend_x=-0.05, legend_y=1.1
                 )
fig.show()