[英]Compare dates in T-SQL
I have a table with a column date
of datatype varchar
.我有一个数据类型为
varchar
的列date
的表。 The values are '2022-03-08 07:00',2022-03-08 07:30...
.值为
'2022-03-08 07:00',2022-03-08 07:30...
In my stored procedure I have a parameter of type DATE
and with a value '2022-3-8'
在我的存储过程中,我有一个
DATE
类型的参数,其值为'2022-3-8'
DECLARE @d DATE = '2022-3-8'
SELECT *, r.date AS date, @d AS d
FROM Readings AS r
WHERE CONVERT(VARCHAR, r.date, 23) = @d
How can I compare these two?我如何比较这两者? I get this error:
我收到此错误:
Conversion failed when converting date and/or time from character string.
从字符串转换日期和/或时间时转换失败。
I would like to remove time component and compare '2022-03-08'
vs '2022-3-8'
.我想删除时间分量并比较
'2022-03-08'
与'2022-3-8'
。 Notice leading zero in month and day numbers.请注意月份和日期数字中的前导零。
TRY_CAST
or TRY_CONVERT
will convert your string into date and return null if that is not possible. TRY_CAST
或TRY_CONVERT
会将您的字符串转换为日期,如果不可能则返回 null。
SELECT *, TRY_CAST(r.date AS DATE) as date, @d AS d
FROM Readings r
WHERE TRY_CAST(r.date AS DATE) = @d
Example:例子:
DECLARE @d DATE = '2022-3-8';
WITH Readings AS
(
SELECT '2022-03-08 07:00' AS date
UNION ALL
SELECT '2022-03-08 07:30'
UNION ALL
SELECT '2022-03-06 17:30' --will be false
UNION ALL
SELECT '2022-02-31 07:30' --invalid string
)
SELECT r.date as OriginalString
, TRY_CAST(r.date AS DATE) as CastDate
, TRY_CONVERT(DATE,r.date,23) as ConvertDate
, @d AS d
, CASE WHEN TRY_CAST(r.date AS DATE) = @d THEN 1 ELSE 0 END AS Matched
FROM Readings r
use right(replicate('0',2)+value,2) that enables you to change a 1 one_digit number to two_digit number ( 1=>01 ).使用right(replicate('0',2)+value,2)使您能够将1 个一位数更改为两位数( 1=>01 )。 use PARSENAME for split and concat for connect strings
使用PARSENAME进行拆分,使用concat进行连接字符串
DECLARE @d DATE = '2022-3-8'
SELECT Concat(( Parsename(Replace(@d, '-', '.'), 3) )/*year*/, '-', RIGHT(
Replicate('0', 2) + ( Parsename(Replace(@d, '-', '.'), 2) ), 2)
/*month*/,
'-', RIGHT(Replicate('0', 2) + ( Parsename(Replace(@d, '-', '.'),
1) ), 2
)/*day*/) as d
or in your query或在您的查询中
DECLARE @d DATE = '2022-3-8'
SELECT *,
r.date
AS date,
,@d
FROM readings AS r
WHERE CONVERT(VARCHAR, r.date, 23) =
Concat(( Parsename(Replace(@d, '-', '.'), 3) )/*year*/, '-', RIGHT(
Replicate('0', 2) + ( Parsename(Replace(@d, '-', '.'), 2) ), 2)/*month*/,
'-',
RIGHT(Replicate('0', 2) + ( Parsename(Replace(@d, '-', '.'), 1) ), 2)
/*day*/)
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