[英]Join 2 columns of different number of rows in R
I am trying to create a dataframe with two columns with different number of rows, but I have no idea how to do it.我正在尝试创建一个 dataframe,其中包含两列,行数不同,但我不知道该怎么做。 Basically I would complete the lower columns with NA.
基本上我会用 NA 完成下面的列。 Follow the code:
按照代码:
data.frame(Week1_data, Week2_data)
The error is:错误是:
arguments imply differing number of rows: 802, 1103```
There is a cbind.na
which does pad with NA
for the shorter length object有一个
cbind.na
,它用NA
填充较短的长度 object
qpcR:::cbind.na(Week1_data, Week2_data)
Week1_data Week2_data
[1,] 1 1
[2,] 2 2
[3,] 3 3
[4,] 4 4
[5,] 5 5
[6,] NA 6
[7,] NA 7
Output is a matrix
, it can be converted to data.frame
with as.data.frame
Output是一个
matrix
,可以用as.data.frame
转成data.frame
Or using base R
或者使用
base R
mx <- max(length(Week1_data), length(Week2_data))
data.frame(lapply(list(Week1_data = Week1_data,
Week2_data = Week2_data), `length<-`, mx))
Week1_data Week2_data
1 1 1
2 2 2
3 3 3
4 4 4
5 5 5
6 NA 6
7 NA 7
Week1_data <- 1:5
Week2_data <- 1:7
Another possible solution, using base R merge
:另一种可能的解决方案,使用 base R
merge
:
Week1_data <- 8:10
Week2_data <- 2:5
merge(cbind(Week1_data, X=1:length(Week1_data)),
cbind(Week2_data, X=1:length(Week2_data)), all.y =T)[-1]
#> Week1_data Week2_data
#> 1 8 2
#> 2 9 3
#> 3 10 4
#> 4 NA 5
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