使用 R：如何在每年对这些计数的数字进行分组时计算落入特定容器的元素数量？

Question

I am working with daily temperature data (set as dates in a year-month-day style) which I have binned in temperature bins using c(-20,-10,0,10,20,30,40) as breaks. I now have a data frame looking like that

    date         meantemp      bin
1 1980-01-01     -0.1026295  (-10,0]
2 1980-01-02     -0.8921732  (-10,0]
3 1980-01-03     -2.9833818  (-10,0]
4 1980-01-04     -0.6400758  (-10,0]
5 1980-01-05      2.0644677   (0,10]
6 1980-01-06      2.5712572   (0,10]

I got the table with the number of all days for the time span 1980 to today by using:

Summary(df %>% filter(date >= as.Date('1980-01-01') & date <= as.Date('1980-12-31')))


date                meantemp        temp_bin  

Min.   :1980-01-01   Min.   :-8.004   (-20,-10]:  0  

1st Qu.:1980-04-01   1st Qu.: 3.695   (-10,0]  : 40  
Median :1980-07-01   Median : 8.323   (0,10]   :160  

Mean   :1980-07-01   Mean   : 8.524   (10,20]  :155  

3rd Qu.:1980-09-30   3rd Qu.:14.029   (20,30]  : 11  

Max.   :1980-12-31   Max.   :22.560   (30,40]  :  0  

Now, is there a way I can create a table that gives me the number of days in each bin per year?

I am looking for something like this:

       (-20,-10] (-10,0]   (0,10]   (10,20]    (20,30]    (30,40]

1980       0          40      160       155        11         0
1981        5        50       100       150        57         3

I am new to R so the answer to my question might be a bit obvious. Nevertheless, thanks in advance!

Answer 1

You need year to get the year of the date, and table to count the observation.

library(lubridate)

with(df, table(year(date), bin))

      bin
       (-10,0] (0,10]
  1980       4      2