最后计算一行中每一列的平均值

Question

I'm trying to get a calculation at the end of the table that averages each column. I can't seem to get my head working right on this.

This is my query:

SELECT profiles.id, min (total_connections_average) from profiles

inner join connections ON from_profile_id = profiles.id

    inner join (

        select sq.from_profile_id,

        count (sq.countn) as total_connections_average 
            from (

            select from_profile_id, cast (accepted_at as date), count (*) as countn from connections

            group by from_profile_id, cast (accepted_at as date)
            ) as sq

        group by sq.from_profile_id
        
            ) sq ON sq.from_profile_id = profiles.id
    
where profiles.id in ('1','2','3','4','25','26')
    
group by profiles.id

Resulting data from the query:

id	min
1	31
2	11
3	21
4	8
25	9
26	6

I'd like to have a row at the end with an average calculation for each column eg:

id	min
1	31
2	11
3	21
4	8
25	9
26	6
10.16666667	14.33333333

Much appreciate any help.

Answer 1

The best I can think of is a union with the previous query. This is a quick fix what I came up

SELECT profiles.id, min (total_connections_average) min from profiles

inner join connections ON from_profile_id = profiles.id

inner join (

select sq.from_profile_id,

count (sq.countn) as total_connections_average
from (

select from_profile_id, cast (accepted_at as date), count (*) as countn from connections

group by from_profile_id, cast (accepted_at as date)
) as sq

group by sq.from_profile_id

) sq ON sq.from_profile_id = profiles.id

where profiles.id in ('1','2','3','4','25','26')

group by profiles.id

#this is union for average last column

union

select avg(agg.id), avg(agg.min)
from (
SELECT profiles.id, min (total_connections_average) min from profiles

inner join connections ON from_profile_id = profiles.id

inner join (

select sq.from_profile_id,

count (sq.countn) as total_connections_average
from (

select from_profile_id, cast (accepted_at as date), count (*) as countn from connections

group by from_profile_id, cast (accepted_at as date)
) as sq

group by sq.from_profile_id

) sq ON sq.from_profile_id = profiles.id

where profiles.id in ('1','2','3','4','25','26')

group by profiles.id
) agg