JavaScript 比较两个 arrays 并将在第二个数组中具有相同属性值的项目推送到第一个数组

Question

I have two arrays and want to push the values from the second array having the same property value. Comparing the values by using addrSeq property and push the matching object in to vpainfo array

Below are the sample JSON structure,

Array1 :

[
  {
    "addrSeq": "12",
    "accountMask": "********7479",
    "vpainfo": []
  },
  {
    "addrSeq": "13",
    "accountMask": "********74",
    "vpainfo": []
  }
]

Array2:

[
  {
    "addrSeq": "12",
    "vpa": "saasasa@fff"
  },
  {
    "addrSeq": "12",
    "vpa": "xyz@com"
  },
  {
    "addrSeq": "13",
    "vpa": "saas@ddd"
  }
]

Answer 1

you just need to learn javascript, here is result please look into this i just store both into array, and then run loop and match and push into one.

    let firstarray =[
  {
    "addrSeq": "12",
    "accountMask": "********7479",
    "vpainfo": []
  },
  {
    "addrSeq": "13",
    "accountMask": "********74",
    "vpainfo": []
  }
]

let secondarray = [
  {
    "addrSeq": "12",
    "vpa": "saasasa@fff"
  },
  {
    "addrSeq": "12",
    "vpa": "xyz@com"
  },
  {
    "addrSeq": "13",
    "vpa": "saas@ddd"
  }
]
// merge both array into one using addrSeq match value 
let mergedarray = firstarray.map(function(item) {
    secondarray.map(function(item2) {
        if (item.addrSeq == item2.addrSeq) {
            item.vpainfo.push(item2);
        }
    });
  return item;
});

console.log(mergedarray);

Answer 2

You can achieve it via simple forEach loop.

Demo:

 const array1 = [ { "addrSeq": "12", "accountMask": "********7479", "vpainfo": [] }, { "addrSeq": "13", "accountMask": "********74", "vpainfo": [] } ]; const array2 = [ { "addrSeq": "12", "vpa": "saasasa@fff" }, { "addrSeq": "12", "vpa": "xyz@com" }, { "addrSeq": "13", "vpa": "saas@ddd" } ]; array2.forEach((obj) => { array1.forEach((array1Obj) => { if (obj.addrSeq === array1Obj.addrSeq) { array1Obj.vpainfo.push(obj.vpa) } }); }); console.log(array1);

Answer 3

Assuming that the OP requires Array1 to be updated such that each object's vpaIinfo array gets updated based on the data in Array2 , the following solution may be one possible way to achieve the desired objective.

Code Snippet

 const getUpdatedArr = (ar1, ar2) => ( ar1.map( obj => ({...obj, vpainfo: [...obj.vpainfo, ...ar2.filter( ({addrSeq}) => (obj.addrSeq === addrSeq) ).map( ({vpa}) => vpa ) ] }) ) ); const arr1 = [ { "addrSeq": "12", "accountMask": "********7479", "vpainfo": [] }, { "addrSeq": "13", "accountMask": "********74", "vpainfo": [] } ]; const arr2 = [ { "addrSeq": "12", "vpa": "saasasa@fff" }, { "addrSeq": "12", "vpa": "xyz@com" }, { "addrSeq": "13", "vpa": "saas@ddd" } ]; console.log(getUpdatedArr(arr1, arr2));

Explanation

• Iterate over array-1 using .map()
• For each object, keep the rest of the props as-is & manipulate only vpainfo
• Retain any existing values in current vpainfo (using ...obj.vpainfo )
• Append to this, any relevant vpa found in array-2
• The above is accomplished by using .filter() to retain only those with same addrSeq -AND- then, using .map() to extract just the vpa prop (using de-structuring)

Answer 4

Logic

• Loop through first array
• Find the matching items from second array by comparing the addrSeq values.
• Update the vpainfo of item in first array as the concatenated value of vpa s from second array.

Working Fiddle

 const arr1 = [ { "addrSeq": "12", "accountMask": "********7479", "vpainfo": [] }, { "addrSeq": "13", "accountMask": "********74", "vpainfo": [] } ] const arr2 = [ { "addrSeq": "12", "vpa": "saasasa@fff" }, { "addrSeq": "12", "vpa": "xyz@com" }, { "addrSeq": "13", "vpa": "saas@ddd" } ] arr1.forEach((node) => node.vpainfo = node.vpainfo.concat(arr2.filter(item => item.addrSeq === node.addrSeq).map(item => item.vpa))) console.log(arr1);