I have two arrays and want to push the values from the second array having the same property value. Comparing the values by using addrSeq
property and push the matching object in to vpainfo
array
Below are the sample JSON structure,
Array1 :
[
{
"addrSeq": "12",
"accountMask": "********7479",
"vpainfo": []
},
{
"addrSeq": "13",
"accountMask": "********74",
"vpainfo": []
}
]
Array2:
[
{
"addrSeq": "12",
"vpa": "saasasa@fff"
},
{
"addrSeq": "12",
"vpa": "xyz@com"
},
{
"addrSeq": "13",
"vpa": "saas@ddd"
}
]
you just need to learn javascript, here is result please look into this i just store both into array, and then run loop and match and push into one.
let firstarray =[
{
"addrSeq": "12",
"accountMask": "********7479",
"vpainfo": []
},
{
"addrSeq": "13",
"accountMask": "********74",
"vpainfo": []
}
]
let secondarray = [
{
"addrSeq": "12",
"vpa": "saasasa@fff"
},
{
"addrSeq": "12",
"vpa": "xyz@com"
},
{
"addrSeq": "13",
"vpa": "saas@ddd"
}
]
// merge both array into one using addrSeq match value
let mergedarray = firstarray.map(function(item) {
secondarray.map(function(item2) {
if (item.addrSeq == item2.addrSeq) {
item.vpainfo.push(item2);
}
});
return item;
});
console.log(mergedarray);
You can achieve it via simple forEach
loop.
Demo:
const array1 = [ { "addrSeq": "12", "accountMask": "********7479", "vpainfo": [] }, { "addrSeq": "13", "accountMask": "********74", "vpainfo": [] } ]; const array2 = [ { "addrSeq": "12", "vpa": "saasasa@fff" }, { "addrSeq": "12", "vpa": "xyz@com" }, { "addrSeq": "13", "vpa": "saas@ddd" } ]; array2.forEach((obj) => { array1.forEach((array1Obj) => { if (obj.addrSeq === array1Obj.addrSeq) { array1Obj.vpainfo.push(obj.vpa) } }); }); console.log(array1);
Assuming that the OP requires Array1
to be updated such that each object's vpaIinfo
array gets updated based on the data in Array2
, the following solution may be one possible way to achieve the desired objective.
Code Snippet
const getUpdatedArr = (ar1, ar2) => ( ar1.map( obj => ({...obj, vpainfo: [...obj.vpainfo, ...ar2.filter( ({addrSeq}) => (obj.addrSeq === addrSeq) ).map( ({vpa}) => vpa ) ] }) ) ); const arr1 = [ { "addrSeq": "12", "accountMask": "********7479", "vpainfo": [] }, { "addrSeq": "13", "accountMask": "********74", "vpainfo": [] } ]; const arr2 = [ { "addrSeq": "12", "vpa": "saasasa@fff" }, { "addrSeq": "12", "vpa": "xyz@com" }, { "addrSeq": "13", "vpa": "saas@ddd" } ]; console.log(getUpdatedArr(arr1, arr2));
Explanation
.map()
vpainfo
vpainfo
(using ...obj.vpainfo
)vpa
found in array-2 .filter()
to retain only those with same addrSeq
-AND- then, using .map()
to extract just the vpa
prop (using de-structuring)Logic
addrSeq
values.vpainfo
of item in first array as the concatenated value of vpa
s from second array.Working Fiddle
const arr1 = [ { "addrSeq": "12", "accountMask": "********7479", "vpainfo": [] }, { "addrSeq": "13", "accountMask": "********74", "vpainfo": [] } ] const arr2 = [ { "addrSeq": "12", "vpa": "saasasa@fff" }, { "addrSeq": "12", "vpa": "xyz@com" }, { "addrSeq": "13", "vpa": "saas@ddd" } ] arr1.forEach((node) => node.vpainfo = node.vpainfo.concat(arr2.filter(item => item.addrSeq === node.addrSeq).map(item => item.vpa))) console.log(arr1);
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