[英]Select data based on a day in a month, "If date is lesser than a day in a month"
I have a dataset with a column date like this:我有一个包含日期列的数据集,如下所示:
id ![]() |
date![]() |
---|---|
1 ![]() |
2018-02-13 ![]() |
2 ![]() |
2019-02-28 ![]() |
3 ![]() |
2014-01-23 ![]() |
4 ![]() |
2021-10-28 ![]() |
5 ![]() |
2022-01-23 ![]() |
6 ![]() |
2019-09-28 ![]() |
I want to select data that have a date lesser than 15th February我想要 select 日期小于 2 月 15 日的数据
I tried an ifelse statement to define 15th february for each year in my database but i want to know if there is an easier way to do so !我尝试使用 ifelse 语句在我的数据库中定义每年的 2 月 15 日,但我想知道是否有更简单的方法!
Here's the result i'm expecting这是我期待的结果
id ![]() |
date![]() |
---|---|
1 ![]() |
2018-02-13 ![]() |
3 ![]() |
2014-01-23 ![]() |
5 ![]() |
2022-01-23 ![]() |
Thanks in advance提前致谢
You could use lubridate
你可以使用
lubridate
library(lubridate)
library(dplyr)
d %>% filter(month(date)<2 | (month(date)==2 & day(date)<=15))
Output: Output:
id date
1 1 2018-02-13
2 3 2014-01-23
3 5 2022-01-23
This is a base R option.这是一个基本的 R 选项。 Using
format
check if the month/year is between January 1st and February 15th.使用
format
检查月份/年份是否在 1 月 1 日和 2 月 15 日之间。
df[between(format(df$date, "%m%d"), "0101", "0215"),]
Output Output
id date
1 1 2018-02-13
3 3 2014-01-23
5 5 2022-01-23
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