如何根据条件检查对象数组中的重复属性 javascript

Question

I have array of object arrayobj in which have to check property value of

code and type based on condition return statement no add or can add in javascript

in arrobj for type-local, if type local and code values not reappearing in other object return ' can add ' else return 'no add'

in arrobj for type-FL or FL Travel, if different type and code values reappearing in other object return ' can add '

in arrobj for type-FL or FL Travel if type and code both reappearing in object return ' no add '

How to check above condition in javascript,

have tried code without checking property type , got stuck

function checkValues(arrob){
 const checkcode = arrob.map(elem => elem.code);
if (arrob.length !== new Set(checkcode).size) {
 return "no add";
} else {
 return "can add"
}
}
checkValues(arrobj1);
checkValues(arrobj2);
checkValues(arrobj3);

sample objects for scenario

var  arrobj1=[
  {id:1, name: "ram", code: "NIXZ", type: "Local"},
  {id:2, name: "abey", code: "ABCN", type: "FI"},
  {id:3, name: "jaz", code: "ABCN", type: "FI Travel"}
]
var  arrobj2=[
  {id:1, name: "ram", code: "NIXZ", type: "Local"},
  {id:4, name: "zain", code: "NIXZ", type: "FI"},
  {id:2, name: "abey", code: "ABCN", type: "FI"},
  {id:3, name: "jaz", code: "ABCNE", type: "FI Travel"}
]
var  arrobj3=[
  {id:1, name: "ram", code: "NIXZ", type: "Local"},
  {id:4, name: "sam", code: "ABCN", type: "FI"},
  {id:2, name: "abey", code: "ABCN", type: "FI"},
  {id:3, name: "jaz", code: "ABCNE", type: "FI Travel"}
]

Expected Result

//for arrobj1 [type-FL or FL Travel, different type and same code appears]
can add

//for arrobj2 [type local, same code appears] 
no add

//for arrobj3 [type-FL or FL Travel, same type and same code appears] 
no add

Answer 1

The map() method creates a new array populated with the results of calling a provided function on every element in the calling array.

const rawArray = [arrobj1 , arrobj2 , arrobj3]
const hasDups = (objArray) => {
    objArray.ForEach(el => {
        if (objArray.Includes(el.type))
            return true;
        return false;
    });    
}
const newArray = rawArray.map(el => !hasDups(el));