如何根據條件檢查對象數組中的重復屬性 javascript

Question

我有 object arrayobj數組，其中必須檢查的屬性值

javascript中基於條件返回語句的code和type no add或can add

在 arrobj for type-local, if type local and code values not reappearing in other object返回“可以添加”，否則返回“不添加”

在 arrobj for type-FL or FL Travel, if different type and code values reappearing in other object返回 '可以添加'

在 arrobj for type-FL or FL Travel if type and code both reappearing in object返回“不添加”

如何在javascript中查看以上情況，

在不檢查屬性type的情況下嘗試了代碼，卡住了

function checkValues(arrob){
 const checkcode = arrob.map(elem => elem.code);
if (arrob.length !== new Set(checkcode).size) {
 return "no add";
} else {
 return "can add"
}
}
checkValues(arrobj1);
checkValues(arrobj2);
checkValues(arrobj3);

sample objects for scenario

var  arrobj1=[
  {id:1, name: "ram", code: "NIXZ", type: "Local"},
  {id:2, name: "abey", code: "ABCN", type: "FI"},
  {id:3, name: "jaz", code: "ABCN", type: "FI Travel"}
]
var  arrobj2=[
  {id:1, name: "ram", code: "NIXZ", type: "Local"},
  {id:4, name: "zain", code: "NIXZ", type: "FI"},
  {id:2, name: "abey", code: "ABCN", type: "FI"},
  {id:3, name: "jaz", code: "ABCNE", type: "FI Travel"}
]
var  arrobj3=[
  {id:1, name: "ram", code: "NIXZ", type: "Local"},
  {id:4, name: "sam", code: "ABCN", type: "FI"},
  {id:2, name: "abey", code: "ABCN", type: "FI"},
  {id:3, name: "jaz", code: "ABCNE", type: "FI Travel"}
]

預期結果

//for arrobj1 [type-FL or FL Travel, different type and same code appears]
can add

//for arrobj2 [type local, same code appears] 
no add

//for arrobj3 [type-FL or FL Travel, same type and same code appears] 
no add

Answer 1

map() 方法創建一個新數組，其中填充了對調用數組中每個元素調用提供的 function 的結果。

const rawArray = [arrobj1 , arrobj2 , arrobj3]
const hasDups = (objArray) => {
    objArray.ForEach(el => {
        if (objArray.Includes(el.type))
            return true;
        return false;
    });    
}
const newArray = rawArray.map(el => !hasDups(el));