[英]Alternative for re.findall for python
I am using an arduino uno and a thermistor to measure the current temperature.我正在使用 arduino uno 和热敏电阻来测量当前温度。 I have been using re.findall to find the matching string in line 4, is there an alternative instead of using re.findall that has the same function?
我一直在使用 re.findall 来查找第 4 行中的匹配字符串,是否有替代方法而不是使用具有相同 function 的 re.findall? as I am not allowed to use re in my project.
因为我不允许在我的项目中使用 re。 Thanks
谢谢
def my_function(port):
# Set COM Port.....
ser = serial.Serial(port, 9600, timeout=0,
parity=serial.PARITY_NONE, stopbits=serial.STOPBITS_ONE, rtscts=0)
my_function('COM3')
# Set path to my Arduino device
# portPath = my_function
baud = 9600
sample_time = 1 # Takes temperature every 1 second
sim_time = 1 # Graphs 5 data points
# Initializing Lists
# Data Collection
data_log = []
line_data = []
# Establishing Serial Connection
connection = serial.Serial("com3", baud)
# Calculating the length of data to collect based on the
# sample time and simulation time (set by user)
max_length = sim_time / sample_time
# Collecting the data from the serial port
while True:
line = connection.readline()
line_data = re.findall('\d*\.\d*', str(line))
line_data = filter(None, line_data)
line_data = [float(x) for x in line_data]
line_data = [(x - 32) * 0.5556 for x in line_data] # list comprehension to convert line_data temp to celsius
line_data = [round(elem, 2) for elem in line_data] # round temp to 2 dp
if len(line_data) > 0:
print("The current temperature is:" + str(line_data[0]) + " celsius")
break
Looking at this answer here: https://stackoverflow.com/a/4289557/7802476 A slight modification can also give decimals:在这里查看这个答案: https://stackoverflow.com/a/4289557/7802476稍微修改一下也可以给出小数:
>>> txt = "h3110 23 cat 444.4 rabbit 11 2 dog"
>>> [float(s) for s in txt.split() if '.' in s and s.replace('.','').isdigit()]
>>> [444.4]
Your regex \d*\.\d*
will match numbers such as {.2, 2., 2.2,...}
but will not match {2}
since \.
您的正则表达式
\d*\.\d*
将匹配{.2, 2., 2.2,...}
等数字,但不会匹配{2}
,因为\.
has to be in the number.必须在数字中。 The above will also do the same.
上面也会做同样的事情。
EDIT: The solution won't handle numbers that are attached to a string {2.2°C}
where as the regex does.编辑:该解决方案不会像正则表达式那样处理附加到字符串
{2.2°C}
的数字。
To make it handle units as well,为了让它也处理单位,
[float(s.replace(f'{unit}', '')) for s in txt.split()
if '.' in s and s.replace('.','').replace(f'{unit}', '').isdigit()]
Where unit
can be '°C'
or 'F'
for temperature.其中温度
unit
可以是'°C'
或'F'
。
However, your regex matches all floating point numbers attached to any string.但是,您的正则表达式匹配附加到任何字符串的所有浮点数。 That is,
cat2.2rabbit
would also return 2.2
, not sure if this should be returned.也就是说,
cat2.2rabbit
也会返回2.2
,不确定是否应该返回。
Since no sample output is given, Here is a code that extracts all valid numbers from the text:由于没有给出样本 output,下面是从文本中提取所有有效数字的代码:
a = "Temperature = 54.3F 62.5, 79999 54.3°C 23.3C"
a+=' '
temp = []
i = 0
while i < len(a):
if (a[i].isdigit() or a[i] == '.'):
if a[i] == '.' and '.' in temp[-1]:
x = a.find(' ', i)
i = x
temp.pop()
elif i == 0:
temp[-1] += a[i]
elif len(temp)>0 and a[i-1] == temp[-1][-1]:
temp[-1] += a[i]
else:
temp.append(a[i])
i += 1
temp = list(map(float, temp)) # Float casting
print(temp)
Output: Output:
['54.3', '62.5', '79999', '54.3', '23.3']
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