如果我将一个double转换为int会发生什么，但double的值超出范围？

Question

What happens if I cast a double to an int, but the value of the double is out of range?

Lets say I do something like this?

double d = double(INT_MIN) - 10000.0;
int a = (int)d;

What is the value of a? Is it undefined?

Answer 1

Precisely. Quoting from the Standard, 4.9, "The behavior is undefined if the truncated value cannot be represented in the destination type."

Answer 2

David Thornley answered this question completely already. However to deal with this situation in your code you should consider boost's numeric_cast .

double d = double(INT_MIN) - 10000.0;
int a = boost::numeric_cast<int>(d);

This will throw an exception at runtime if d is too big for an int .