[英]How to stop a while loop after n iterations?
I'm learning python and I am trying to create the guess game with two levels of difficulty: easy (10 tries) and difficult (5 tries).我正在学习 python 并且我正在尝试创建具有两个难度级别的猜谜游戏:简单(10 次尝试)和困难(5 次尝试)。 My code works well, but I need to force the while loop to stop asking for the guess after 5 tries in the difficult level and 10 tries in the easy level.
我的代码运行良好,但我需要强制 while 循环在困难级别尝试 5 次和简单级别尝试 10 次后停止询问猜测。 However, with my code I did not reach my goal as the while loop does not stop after n variable < 5 or 10. How can I reach this goal this using the code below:
但是,使用我的代码我没有达到我的目标,因为 while 循环在 n 变量 < 5 或 10 之后不会停止。我如何使用下面的代码达到这个目标:
from random import *
def levels():
user_level=input('Type E for easy level and D for difficult level: ')
if user_level=='e':
easy_level()
else:
difficult_level()
number=randint(1,100)
def difficult_level():
n= 0
while n < 5:
user_number=int(input('Guess the number: '))
if user_number > number:
print('Too high')
elif user_number < number:
print('Too low')
elif user_number == number:
print(f'You guessed the number {number}! Congratulations!')
play_again=input('Would you like to play again? type y for yes or n for no: ')
if play_again =='y':
levels()
else:
print('Bye')
break
print('Sorry, no more attempts :(')
def easy_level():
n= 0
while n < 10:
user_number=int(input('Guess the number: '))
if user_number > number:
print('Too high')
elif user_number < number:
print('Too low')
elif user_number == number:
print(f'You guessed the number {number}! Congratulations!')
play_again=input('Would you like to play again? type y for yes or n for no: ')
if play_again =='y':
levels()
else:
print('Bye')
break
print('Sorry, no more attempts :(')
levels()
Looks like you forgot to increment n
in your loops, so n
is always = 0. Usually you increment your "tracker" variable at the start of the loop or the end of the loop.看起来您忘记在循环中递增
n
,因此n
始终 = 0。通常您在循环开始或循环结束时递增“tracker”变量。 Incrementing in python can be done with n += 1
.递增 python 可以用
n += 1
完成。
The short answer is that you need to add a n += 1
in the while loops, like that:简短的回答是你需要在 while 循环中添加一个
n += 1
,就像这样:
def easy_level():
n= 0
while n < 10:
user_number=int(input('Guess the number: '))
if user_number > number:
print('Too high')
elif user_number < number:
print('Too low')
elif user_number == number:
print(f'You guessed the number {number}! Congratulations!')
play_again=input('Would you like to play again? type y for yes or n for no: ')
if play_again =='y':
levels()
else:
print('Bye')
break
n += 1
print('Sorry, no more attempts :(')
Long answer is that you should really consider using a for loop instead, here is an example of how you can do that:长答案是你真的应该考虑使用 for 循环,下面是一个如何做到这一点的例子:
def easy_level():
for i in range(10)
user_number=int(input('Guess the number: '))
if user_number > number:
print('Too high')
elif user_number < number:
print('Too low')
elif user_number == number:
print(f'You guessed the number {number}! Congratulations!')
play_again=input('Would you like to play again? type y for yes or n for no: ')
if play_again =='y':
levels()
else:
print('Bye')
break
print('Sorry, no more attempts :(')
And you should make your script a lot cleaner by removing the repetitive code like this:你应该通过删除像这样的重复代码来使你的脚本更清晰:
from random import *
def chooseLevel():
user_level=input('Type E for easy level and D for difficult level: ')
if user_level=='e':
return 10
else:
return 5
number = randint(1,100)
for i in range(chooseLevel()):
user_number = int(input('Guess the number: '))
if user_number > number:
print('Too high')
elif user_number < number:
print('Too low')
elif user_number == number:
print(f'You guessed the number {number}! Congratulations!')
play_again = input('Would you like to play again? type y for yes or n for no: ')
if play_again =='y':
levels()
else:
print('Bye')
break
print('Sorry, no more attempts :(')
Here I removed the two functions that you had and I made it so that there is only one loop which makes the code a lot cleaner, I also changed the levels()
function name to chooseLevel()
to make it clearer on what the function does and I also added spaces between the =
which makes things look cleaner.在这里,我删除了你拥有的两个函数,我做了它,以便只有一个循环使代码更清晰,我还将
levels()
function 名称更改为chooseLevel()
以使其更清楚 function 的作用我还在=
之间添加了空格,这让事情看起来更干净。
I also used the for loop like this for i in range(chooseLevel())
Which means that if the chooseLevel()
function returned a 5
it will be as if I wrote for i in range(5)
and if the chooseLevel()
function returns a 10
it will be as if I wrote for i in range(10)
我还使用了这样的 for 循环
for i in range(chooseLevel())
这意味着如果chooseLevel()
function 返回5
就好像我for i in range(5)
如果chooseLevel()
function返回10
就好像我写了for i in range(10)
Thanks.谢谢。
You need to increment n after each iteration, by either reassigning n
(ex. n = n + 1
), or using the +=
operator like this:您需要在每次迭代后递增 n,方法是重新分配
n
(例如n = n + 1
),或使用+=
运算符,如下所示:
from random import *
def levels():
user_level=input('Type E for easy level and D for difficult level: ')
if user_level=='e':
easy_level()
else:
difficult_level()
number=randint(1,100)
def difficult_level():
n= 0
while n < 5:
user_number=int(input('Guess the number: '))
if user_number > number:
print('Too high')
elif user_number < number:
print('Too low')
elif user_number == number:
print(f'You guessed the number {number}! Congratulations!')
play_again=input('Would you like to play again? type y for yes or n for no: ')
if play_again =='y':
levels()
else:
print('Bye')
break
n += 1 # increment n after each iteration
print('Sorry, no more attempts :(')
def easy_level():
n= 0
while n < 10:
user_number=int(input('Guess the number: '))
if user_number > number:
print('Too high')
elif user_number < number:
print('Too low')
elif user_number == number:
print(f'You guessed the number {number}! Congratulations!')
play_again=input('Would you like to play again? type y for yes or n for no: ')
if play_again =='y':
levels()
else:
print('Bye')
break
n += 1 # increment n after each iteration
print('Sorry, no more attempts :(')
levels()
Probably easier to use a for
loop like so:像这样使用
for
循环可能更容易:
def levels():
easy_turns = 5
hard_turns = 10
user_level=input('Type E for easy level and D for difficult level: ')
if user_level=='e':
play(easy_turns)
else:
play(hard_turns)
def play(turns):
for _ in range(turns):
user_number=int(input('Guess the number: '))
if user_number > number:
print('Too high')
elif user_number < number:
print('Too low')
elif user_number == number:
print(f'You guessed the number {number}! Congratulations!')
play_again=input('Would you like to play again? type y for yes or n for no: ')
if play_again =='y':
levels()
else:
print('Bye')
break
print('Sorry, no more attempts :(')
A good rule of thumb is if you are using the same code twice put it in a function. It's sure to get out of sync over time then you'll be wondering why "easy" works but "hard" does something odd (or some variation of that).一个好的经验法则是,如果您两次使用相同的代码,请将其放入 function。随着时间的推移,它肯定会不同步,那么您会想知道为什么“简单”有效,但“困难”却做了一些奇怪的事情(或一些的变化)。
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