获取每个分组的唯一元素并写入 Pandas Python 中的列

Question

I have a data frame like so:

Input:

year ip   type
2020 101  Missing
2021 101  Type 1
2022 101  Type 2
2020 102  Missing
2021 102  Missing
2020 103  Missing
2021 103  Type 2
2021 104  Type 1
2022 104  Type 2
2022 104  Type 2

How can I convert my data frame to the following:

Expected Output:

ip  type
101 Missing/Type 1/Type 2
102 Missing
103 Missing/Type 2
104 Type 1/Type 2

Where I get all unique types for each IP. How can I do this in python pandas?

Answer 1

In your case do drop_duplicates before groupby.agg

out = df.drop_duplicates(['ip','type']).groupby('ip')['type'].agg('/'.join).reset_index()
Out[638]: 
    ip                 type
0  101  Missing/Type1/Type2
1  102              Missing
2  103        Missing/Type2
3  104          Type1/Type2

Answer 2

You can try drop_duplicates then agg

out = df.drop_duplicates(['ip', 'type']).groupby('ip', as_index=False).agg('/'.join)

print(out)


    ip                   type
0  101  Missing/Type 1/Type 2
1  102                Missing
2  103         Missing/Type 2
3  104          Type 1/Type 2