infile 到一个字符数组，一次一个字符，没有字符串

Question

I'm trying to get input from a file, but I need to do it one char at a time into a character array. There are no numbers or symbols, but it only prints out the first letter.

Answer 1

Your use of inFile.eof() is wrong . Move the read operation into the loop condition instead. And, consider using inFile.get(...) instead of inFile >> ... in this situation.

But, more importantly, your code prints out only 1 character because you are return 'ing at the end of the 1st loop iteration. Get rid of the return statement inside the loop, it doesn't belong there at all.

Also, your cout statement inside the loop is printing out the wrong array element, because you are incrementing numofCharacters before passing the read character to cout . And, your loop has a potential buffer overflow, if the input file has more than 35 characters in it.

Try this loop instead:

while ((numofCharacters < 35) &&
       inFile.get(note1[numofCharacters]) /*inFile >> note1[numofCharacters]*/)
{
    cout << note1[numofCharacters];
    ++numofCharacters;

    /* or:
    ++numofCharacters;
    cout << note1[numofCharacters-1];
    */
}