动态char字段一次读取一个char

Question

#include <stdio.h>
#include <iostream>

using namespace std;

int main()
{

char * text = new char;
scanf("%c", text);
scanf("%c", text+1);

return 0;
}    

Sorry for this lame question... I'm trying to read a string one char at a time (because I need to check sth for every char..) For input "ab" the output is "ab" and a ?random? character... It doesn't work without the 'scanf("%c", text+1);' either.. I can do this using static field, but this version gives me one extra char in the end.. What am I doing wrong? :'(

Answer 1

You allocate one char giving you the pointer text . You then access text[0] and text[1] which clearly give an out of bounds access. I strongly recommend you don't access memory explicitly and use a std::string instead, eg:

std::string text;
for (std::istreambuf_iterator<char> it(std::cin), end; it != end; ++it) {
    // do whatever checks you need to do
    text.push_back(*it);
}
std::cout << "read '" << text << "'\n";