在C ++中定义二进制宏

Question

Can someone explain why the following error happens:

    #define bla "\xA"
    char a [2] = {0};
    memcpy (a,bla,1); // a[0] = 0x0a <- Correct
    //a[1] = bla;     // '=' : cannot convert from 'const char [2]' to 'char'

Thanks,

RM

Answer 1

The types are different: a[1] is a char and "\\xA" is an array of char.

In C++ and C anything enclosed in double quotes (including nothing) is an array of char.

Answer 2

Try:

#define bla '\xA'

Although that will stop the memcpy working.