[英]How can I get the difference between two dates in hours, omitting the hours on weekends?
I need a function to check how many hours have passed between two dates, but if for example there is a weekend in between, then skip those hours.我需要一个函数来检查两个日期之间已经过去了多少小时,但是如果例如中间有一个周末,那么就跳过这些时间。
Date 1: moment('2022-05-27 20:00:00).tz('UTC')
日期1:
moment('2022-05-27 20:00:00).tz('UTC')
Date 2: moment('2022-05-30 20:00:00).tz('UTC')
日期2:
moment('2022-05-30 20:00:00).tz('UTC')
Expected output: 24 hours
预期输出:
24 hours
I get 25 if I do i <= n
and 24 when I do i < n
如果我做
i <= n
,我得到 25,当我做 i i < n
n 时,我得到 24
But I do not use moment但我不使用时刻
Note that this should work across daylight savings changes in the locale you are in请注意,这应该适用于您所在地区的夏令时更改
const d1 = new Date('2022-05-27 20:00:00') const d2 = new Date('2022-05-30 20:00:00') console.log(d1, d2) let hours = 0; for (let i = d1.getTime(), n = d2.getTime(); i < n; i += 3600000) { const d = new Date(i); if (![0, 6].includes(d.getDay())) hours++; } console.log(hours)
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