简体   繁体   English

Typescript::相关通用约束

[英]Typescript :: Related Generic Constraints

In React , I have a generic interface like so:React中,我有一个像这样的通用接口:

interface BaseProps<T> {
  data: T;
}

The consumers of my code will extend this to define their own Props and Component :我的代码的使用者将扩展它以定义他们自己的PropsComponent

interface MyProps extends BaseProps<string> {
  ...
}
const MyComponent: React.FC<MyProps> = ({ data }) => {
  ...
}

I want to write a method that accepts such a component and returns a value of the same type as MyComponent.data .我想编写一个方法来接受这样的组件并返回与MyComponent.data相同类型的值。 This is what I'm struggling with.这就是我正在努力解决的问题。 I'm trying to write this method and invoke it as:我正在尝试编写此方法并将其调用为:

function myFunc<T, U extends BaseProps<T>>(component: React.FC<U>): T {
  return ...
}
const ret1 = myFunc(MyComponent);
const ret2 = myFunc<string, MyProps>(MyComponent);

ret2 has the correct type string but ret comes out to have unknown type. ret2具有正确的类型string ,但ret结果是unknown类型。 Is there a way I can enforce constraints in the myFunc method such that ret1 is typed correctly without requiring me to explicitly declare types in <> ?有没有一种方法可以在myFunc方法中强制执行约束,以便正确键入ret1而无需我在<>中显式声明类型?

Update更新

Both @futut and @proton have given (almost) identical solution that clearly work in this case! @futut 和@proton 都给出了(几乎)相同的解决方案,在这种情况下显然有效! Kudos!荣誉!

However, the sample code I wrote here was a bit over-simplified.但是,我在这里编写的示例代码有点过分简化了。 If I change the BaseProps interface to:如果我将BaseProps接口更改为:

interface BaseProps<T> {
  callback: (value: T) => void;
}

Then I can no longer use U["data"] .然后我不能再使用U["data"] Is there a way to be able to return a value of the type of value parameter in MyComponent.callback in this case?在这种情况下,有没有办法能够在MyComponent.callback中返回value

PS: Apologies for shifting the goalpost here. PS:很抱歉在这里转移球门柱。 My bad at oversimplifying too much.我不擅长过于简单化。

TypeScript doesn't know that the type U provided can also tell it what T is. TypeScript 不知道提供的类型U也可以告诉它T是什么。 You could instead use a single type parameter and use an indexed access to get the type of its data property:您可以改为使用单个类型参数并使用索引访问来获取其data属性的类型:

function myFunc<T extends BaseProps<any>>(component: React.FC<T>): T["data"] { 
    /* ... */ 
}

Just explicitly inform typescript, that type of BaseProps.data is going to be function return value, like below:只需明确通知 typescript,该类型的BaseProps.data将是 function 返回值,如下所示:

function myFunc<T, U extends BaseProps<T>>(component: React.FC<U>): U['data'] {
  ...
}

That way you won't have to pass types to generic statement ( <> ), as long as your component passed to myFunc is typed properly.这样您就不必将类型传递给泛型语句 ( <> ),只要传递给myFunc的组件类型正确即可。


Edit: Regarding second version of question: Things get tricky here.编辑:关于问题的第二个版本:这里的事情变得棘手。 You can point to value of a callback by using infer keyword like below:您可以使用infer关键字指向回调的值,如下所示:

function myFunc<T extends BaseProps<any>>(
  component: React.FC<T>,
): T['callback'] extends (a: infer R) => void ? R : never {
...

Check documentation regarding that keyword: https://www.typescriptlang.org/docs/handbook/release-notes/typescript-2-8.html检查有关该关键字的文档: https://www.typescriptlang.org/docs/handbook/release-notes/typescript-2-8.html

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM