[英]Getting each column in a 3d numpy array
I converted an image from RBG to CieLab, now I need to use the value of the cielab to calculate some equations.我将图像从 RBG 转换为 CieLab,现在我需要使用 cielab 的值来计算一些方程。 I have been trying to get the value of each column in the array.
我一直在尝试获取数组中每一列的值。 For example if I have:
例如,如果我有:
List =列表 =
[[[ 65 234 169]
[203 191 245]
[ 36 58 196]
[207 208 143]
[251 208 187]]
[[ 79 69 237]
[ 13 124 42]
[104 165 82]
[170 178 178]
[ 66 42 210]]
[[ 40 163 219]
[142 37 140]
[ 75 205 143]
[246 30 221]
[ 16 98 102]]]
How can I get it to give me the values of each columns like:我怎样才能得到它给我每列的值,例如:
1st_column =第一列 =
65
203
36
207
251
79
13
104
170
66
40
142
75
246
16
Thank you.谢谢你。
Try:尝试:
>>> m[:, :, 0]
array([[ 65, 203, 36, 207, 251],
[ 79, 13, 104, 170, 66],
[ 40, 142, 75, 246, 16]])
As suggested by @mozway, you can use the ellipsis syntax: m[..., 0]
.正如@mozway 所建议的,您可以使用省略号语法:
m[..., 0]
。
To know more, read How do you use the ellipsis slicing syntax in Python?要了解更多信息,请阅读如何在 Python 中使用省略号切片语法?
You can also flatten
your array:您还可以
flatten
您的阵列:
>>> m[:, :, 0].flatten()
array([ 65, 203, 36, 207, 251, 79, 13, 104, 170, 66, 40, 142, 75, 246, 16])
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