如何将 std::chrono::duration 转换为提高持续时间

Question

I have two time_point objects in my code and I need to use Boost condition variable for the difference:

template<class Clock, class Dur = typename Clock::duration>
class Time {
    std::chrono::time_point<Clock, Dur> a;
    std::chrono::time_point<Clock, Dur> b;
}
....
boost::condition_variable var;
....
var.wait_for(lock, b - a, [](){ /* something here */}); //<---boost cond var
....

How can I convert b - a to something usable with boost?

Answer 1

I'd do what I always do: avoid duration_cast by using arithmetic with UDL values.

You have to select a resolution for this, let's choose microseconds:

#include <boost/thread.hpp>
#include <chrono>
#include <iostream>
using namespace std::chrono_literals;

template <class Clock, class Dur = typename Clock::duration> //
struct Time {
    std::chrono::time_point<Clock, Dur> a = Clock::now();
    std::chrono::time_point<Clock, Dur> b = a + 1s;

    boost::mutex mx;
    void         foo() {
        //....
        boost::condition_variable var;
        //....
        boost::unique_lock<boost::mutex> lock(mx);

        std::cout << "Waiting " << __PRETTY_FUNCTION__ << "\n";
        auto s = var.wait_for(lock, boost::chrono::microseconds((b - a) / 1us),
                     [] { /* something here */
                          return false;
                     }); //<---boost cond var
        assert(!s);

        //....
    }
};

int main() { 
    Time<std::chrono::system_clock>{}.foo();
    Time<std::chrono::steady_clock>{}.foo();
    std::cout << "\n";
}

Prints (1 second delay each):

Waiting void Time<Clock, Dur>::foo() [with Clock = std::chrono::_V2::system_clock; Dur = std::chrono::duration<long int, std::ratio<1, 1000000000>
>]
Waiting void Time<Clock, Dur>::foo() [with Clock = std::chrono::_V2::steady_clock; Dur = std::chrono::duration<long int, std::ratio<1, 1000000000>
>]

I must say I can't fathom a scenario where the wait time for a condition would be specified as the difference between absolute time points, but I guess that's more of a "your problem" here :)