将具有两个终止号的输入拆分为两个数组c#

Question

Lets assume we have an input from keyboard.

I dont know the length of the input, but I know that the first part is an array of integers, where consecutive groups of three numbers describe assets: type,value,amount .

then termination number is -1 then I have another array of integers and then again termination number -1

For example:

1 500 5 2 25 100 3 10 50 -1 3 9 -1 

So I want to have 2 containers to work with first is {(1,500,5),(2,25,100),(3,10,50)} and second is {3,9} .

How I can make this happen?

Answer 1

This will give you a List of structs containing the asset data triples from the first part of the string, and an array of ints from the second part:

public struct assetData {
    public int type;
    public int value;
    public int amount;
};

void Main()
{
    string keyboard = "1 500 5 2 25 100 3 10 50 -1 3 9 -1";
    string[] parts = keyboard.Split("-1", StringSplitOptions.RemoveEmptyEntries);

    int[] assetInput = parts[0].Trim().Split().Select(int.Parse).ToArray();
    int[] numbers    = parts[1].Trim().Split().Select(int.Parse).ToArray();

    // take 3 numbers at a time into assetData structs. Store them.
    var assetInfo = new List<assetData>();
    for (int i = 0; i < assetInput.Length; i += 3)
    {
        assetData item;
        item.type = assetInput[i];
        item.value = assetInput[i+1];
        item.amount = assetInput[i+2];
        assetInfo.Add(item);
    }
}

variant for array input:

public struct assetData {
    public int type;
    public int value;
    public int amount;
};

void Main()
{
    string keyboard = "1 500 5 2 25 100 3 10 50 -1 3 9 -1";
    int[] input = keyboard.Trim().Split().Select(int.Parse).ToArray();
    
    // 3 numbers at a time into assetData structs. Store them.
    var assetInfo = new List<assetData>();
    int i;
    for (i=0; input[i] != -1; i += 3)
    {
        assetData item;
        item.type = input[i];
        item.value = input[i+1];
        item.amount = input[i+2];
        assetInfo.Add(item);
    }
    
    i++; // skip the -1
    
    var numbers = new List<int>();
    while (i < input.Length - 1) {
        numbers.Add(input[i]);
        i++;
    }
}