如何选择列中第二频繁的值？

Question

Could you please help me with this select query?

countries table in DB AS photo

I need to select the most second frequent (duplicated) country in the column

Output should be like this: IT

Answer 1

SELECT name
FROM Countries
GROUP BY name
ORDER BY count(name) DESC
LIMIT 1,1;

Answer 2

There might be shorter and simpler queries, but this one should work on every DB and prevent issues like the key words LIMIT , TOP etc. can't be used on all different DB's.

SELECT name FROM Countries
GROUP BY name
HAVING COUNT(name) = (SELECT MAX(a.amount) AS amount
FROM (SELECT name, COUNT(name) AS amount
FROM Countries
GROUP BY name) a
WHERE amount < (SELECT MAX(b.amount) FROM
(SELECT name, COUNT(name) AS amount
FROM Countries
GROUP BY name)b));

This query will find step by step the second frequent value of your table using sub queries.

Answer 3

Hello you can use this also

with flo as (
select country , count(*)as cate, dense_rank()over( order by count(*)  desc)as rnk
from yourtable
group by country)
select country from flo 
where rnk=2

Answer 4

i wrote now this query and it worked well too :)

SELECT name FROM Countries GROUP BY name HAVING count(name) = (
SELECT a.amount from (
SELECT DISTINCT COUNT(name) as amount FROM countries GROUP BY name ORDER 
by amount DESC limit 1,1) a  )