在 SQL 列中查找最常见的值

Question

How can I find the most frequent value in a given column in an SQL table?

For example, for this table it should return two since it is the most frequent value:

one
two
two
three

Answer 1

SELECT
  <column_name>,
  COUNT(<column_name>) AS `value_occurrence` 

FROM
  <my_table>

GROUP BY 
  <column_name>

ORDER BY 
  `value_occurrence` DESC

LIMIT 1;

Replace <column_name> and <my_table> . Increase 1 if you want to see the N most common values of the column.

Answer 2

Try something like:

SELECT       `column`
    FROM     `your_table`
    GROUP BY `column`
    ORDER BY COUNT(*) DESC
    LIMIT    1;

Answer 3

Let us consider table name as tblperson and column name as city . I want to retrieve the most repeated city from the city column:

 select city,count(*) as nor from tblperson
        group by city
          having count(*) =(select max(nor) from 
            (select city,count(*) as nor from tblperson group by city) tblperson)

Here nor is an alias name.

Answer 4

Below query seems to work good for me in SQL Server database:

select column, COUNT(column) AS MOST_FREQUENT
from TABLE_NAME
GROUP BY column
ORDER BY COUNT(column) DESC

Result:

column          MOST_FREQUENT
item1           highest count
item2           second highest 
item3           third higest
..
..

Answer 5

For use with SQL Server.

As there is no limit command support in that.

Yo can use the top 1 command to find the maximum occurring value in the particular column in this case (value)

SELECT top1 
    `value`,
    COUNT(`value`) AS `value_occurrence` 
FROM     
    `my_table`
GROUP BY 
    `value`
ORDER BY 
    `value_occurrence` DESC;

Answer 6

Assuming Table is ' SalesLT.Customer ' and the Column you are trying to figure out is ' CompanyName ' and AggCompanyName is an Alias.

Select CompanyName, Count(CompanyName) as AggCompanyName from SalesLT.Customer
group by CompanyName
Order By Count(CompanyName) Desc;

Answer 7

If you can't use LIMIT or LIMIT is not an option for your query tool. You can use "ROWNUM" instead, but you will need a sub query:

SELECT FIELD_1, ALIAS1
FROM(SELECT FIELD_1, COUNT(FIELD_1) ALIAS1
    FROM TABLENAME
    GROUP BY FIELD_1
    ORDER BY COUNT(FIELD_1) DESC)
WHERE ROWNUM = 1

Answer 8

If you have an ID column and you want to find most repetitive category from another column for each ID then you can use below query,

Table:

Query:

SELECT ID, CATEGORY, COUNT(*) AS FREQ
FROM TABLE
GROUP BY 1,2
QUALIFY ROW_NUMBER() OVER(PARTITION BY ID ORDER BY FREQ DESC) = 1;

Result:

Answer 9

Return all most frequent rows in case of tie

Find the most frequent value in mysql,display all in case of a tie gives two possible approaches:

1. Scalar subquery:

    SELECT "country", COUNT(country) AS "cnt" FROM "Sales" GROUP BY "country" HAVING COUNT("country") = ( SELECT COUNT("country") AS "cnt" FROM "Sales" GROUP BY "country" ORDER BY "cnt" DESC, LIMIT 1 ) ORDER BY "country" ASC

2. With the RANK window function, available since MySQL 8+:

    SELECT "country", "cnt" FROM ( SELECT "country", COUNT("country") AS "cnt", RANK() OVER (ORDER BY COUNT(*) DESC) "rnk" FROM "Sales" GROUP BY "country" ) AS "sub" WHERE "rnk" = 1 ORDER BY "country" ASC

   This method might save a second recount compared to the first one.

   RANK works by ranking all rows, such that if two rows are at the top, both get rank 1 . So it basically directly solves this type of use case.

   RANK is also available on SQLite and PostgreSQL, I think it might be SQL standard, not sure.

In the above queries I also sorted by country to have more deterministic results.

Tested on SQLite 3.34.0, PostgreSQL 14.3, GitHub upstream .

Most frequent for each GROUP BY group

• MySQL: MySQL SELECT most frequent by group
• PostgreSQL:
  • Get most common value for each value of another column in SQL
  • https://dba.stackexchange.com/questions/193307/find-most-frequent-values-for-a-given-column
• SQLite: SQL query for finding the most frequent value of a grouped by value

Answer 10

One way I like to use is:

select *<given_column>*,COUNT(*<given_column>*)as VAR1 from Table_Name

group by *<given_column>*

order by VAR1 desc

limit 1