简体   繁体   English

如何存储 std::bind function 指针?

[英]How can I store a std::bind function pointer?

Here is the code I am using这是我正在使用的代码

#include <functional>
#include <iostream>
#include <thread>

class Context {
private:
  std::thread thread;
  bool running;
  void run() {
    while (running) {
      if (function != nullptr) {
        function();
        function = nullptr;
      }
    }
  }
  void (*function)();

public:
  Context() : running(true) { thread = std::thread(&Context::run, this); }
  ~Context() {
    running = false;
    thread.join();
  }

  template <typename T, typename... Args> void call(T function, Args... args) {
    this->function = std::bind(function, args...);
  }
};

// Here are some test functions
void f1() { std::cout << "f1" << std::endl; }

void f2(int a) { std::cout << "f2(" << a << ")" << std::endl; }

void f3(int a, int b) {
  std::cout << "f3(" << a << ", " << b << ")" << std::endl;
}

int main() {
  Context context;
  context.call(f1);
  context.call(f2, 1);
  context.call(f3, 1, 2);
  return 0;
}

I want this class to create a thread that will run some functions.我希望这个 class 创建一个线程来运行一些函数。 The thread will be created when the class is created and will be stopped when the class is destroyed.该线程将在 class 创建时创建,并在 class 销毁时停止。 In order to run a function, you can call the Context::call function with the function to be called and the arguments.为了运行 function,您可以使用要调用的 function 和 arguments 调用 Context::call function。

f2(2);

becomes成为

context.call(f2, 2);

and

f3(3, 4);

becomes成为

context.call(f3, 3, 4);

However I am getting errors when I try to compile this file:但是,当我尝试编译此文件时出现错误:

t.cpp: In instantiation of 'void Context::call(T, Args ...) [with T = void (*)(); Args = {}]':
t.cpp:55:15:   required from here
t.cpp:42:31: error: cannot convert 'std::_Bind_helper<false, void (*&)()>::type' to 'void (*)()' in assignment
   42 |     this->function = std::bind(function, args...);
      |                      ~~~~~~~~~^~~~~~~~~~~~~~~~~~~
      |                               |
      |                               std::_Bind_helper<false, void (*&)()>::type
t.cpp: In instantiation of 'void Context::call(T, Args ...) [with T = void (*)(int); Args = {int}]':
t.cpp:56:15:   required from here
t.cpp:42:20: error: cannot convert 'std::_Bind_helper<false, void (*&)(int), int&>::type' to 'void (*)()' in assignment
   42 |     this->function = std::bind(function, args...);
      |     ~~~~~~~~~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
t.cpp: In instantiation of 'void Context::call(T, Args ...) [with T = void (*)(int, int); Args = {int, int}]':
t.cpp:57:15:   required from here
t.cpp:42:20: error: cannot convert 'std::_Bind_helper<false, void (*&)(int, int), int&, int&>::type' to 'void (*)()' in assignment

I know this code is unsafe and has flaws but I used mutexes and security measures in the real implementation.我知道这段代码不安全并且有缺陷,但我在实际实现中使用了互斥锁和安全措施。 This example is just the minimal to reproduce the error.此示例只是重现错误的最小示例。

You can make use of std::function .您可以使用std::function In particular, replace void (*function)() with std::function<void ()> function as shown below:特别是,将void (*function)()替换为std::function<void ()> function ,如下所示:

class Context {
private:
  //other code here
  
  std::function<void ()> function;

};

Working demo工作演示

I would choose some other approach.我会选择其他方法。 Take a look:看一看:

#include <functional>
#include <iostream>
#include <thread>
using namespace std;

class Context
{
    thread t;

public:
    template<class Func, class... Args>
    Context(Func func, const Args&... args) : t{ func, cref(args)... } {

    }
    ~Context() {
        if (t.joinable())
            t.join();
    }
};

void f1() {
    cout << "f1" << endl;
}

void f2(int) {
    cout << "f2" << endl;
}

void f3(int, int) {
    cout << "f3" << endl;
}

int main()
{
    Context c1{ f1 };
    Context c2{ f2, 1 };
    Context c3{ f3, 1, 2 };
}

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM