如何通过变量/定义的术语插入多个输入并使用代码获得多个输出？ （Python）

Question

I'm trying to make my basic syllable counter run through multiple words, but I do not know how to do so without error. In the code below, I made a placeholder variable containing two words for the code to count syllables of. However, the code ends up not functioning and creates no output. Anyone know what to do?

new_variable = "WORD", "AGAIN"

def syllable_count(word):
    word = word.lower()
    count = 0
    vowels = "aeiouy"
    if word[0] in vowels:
        count += 1
    for index in range(1, len(word)):
        if word[index] in vowels and word[index - 1] not in vowels:
            count += 1
    if word.endswith("e"):
        count -= 1
    if word.endswith("le"):
        count += 1
    if word.endswith("ia"):
        count += 1
    if count == 0:
        count += 1
    if word.endswith("management"):
        count -= 1
    if word.endswith("announcement"):
        count -= 1
    return count


print(syllable_count(new_variable))

Answer 1

As @TimRoberts mentioned in the comments. You are passing a tuple instead of a string to your syllable_counter function.

All you need to do is iterate through the tuple ie new_varieble and then call your syllable_counter for each value.

Just remove your last line and write these two:

for word in new_variable:
    print(syllable_counter(word)) 

Answer 2

new_variable = "WORD", "AGAIN"
print(new_variable)

('WORD', 'AGAIN')

You could try to iterate through the list of new_variable instead, for example:

for new_variable in ["WORD", "AGAIN"]:
    print(syllable_count(new_variable))