在python中将字符串转换为有序列表

Question

top_imdb_movies = ['The Shawshank Redemption', 'The Godfather', 'The Dark Knight']

How would i iterate over top_imdb_movies to display the following ordered list:

1.The Shawshank Redemption
2.The Godfather
3.The Dark Knight

Answer 1

Use enumerate with a start value of 1 as follows:

top_imdb_movies = ['The Shawshank Redemption', 'The Godfather', 'The Dark Knight']

for i, movie in enumerate(top_imdb_movies, 1):
    print(f'{i}. {movie}')

Output:

1. The Shawshank Redemption
2. The Godfather
3. The Dark Knight

Answer 2

top_imdb_movies = ['1. The Shawshank Redemption', '2. The Godfather', '3. The Dark Knight']

for i in top_imbd_movies:
    print(i)

Answer 3

Maybe something like

i=1
for movie in top_imdb_movies:
   print(f"{i}. {movie}"
   i = i+1

Answer 4

top_imdb_movies = ['The Shawshank Redemption', 'The Godfather', 'The Dark Knight']

movie_number=0

for movie_number, movie in enumerate(top_imdb_movies):
    print(f"{movie_number + 1}. {movie}")

output

1. The Shawshank Redemption
2. The Godfather
3. The Dark Knight

Answer 5

By composing functions:

top_imdb_movies = ['The Shawshank Redemption', 'The Godfather', 'The Dark Knight']

print(*map('{}.{}'.format, range(1, 1+len(top_imdb_movies)), top_imdb_movies), sep='\n')

Added the sep='\n' parameter to print and expanding the iterable object with * to avoid the for -loop

---

If the list is long you can define a template string as a variable to gather better performance, template = '{}.{}'

template = '{}.{}'
print(*map(template.format, range(1, 1+len(top_imdb_movies)), top_imdb_movies), sep='\n')