如何在 Linux 中创建脚本以删除目录中的所有文件，只剩下 5 个文件

Question

How to create a script in Linux to delete all files from the directory Condition:- If in the directory only 5 files are left then should not delete any files from that directory.

Answer 1

#! /bin/bash

myPath="/tmp"

myFileList=$(find $myPath -maxdepth 1   -type f)

num=0

for candidate in $myFileList
do
        num=$(($num + 1))

        if [[ $num -le 5 ]]
        then
                echo "do not delete: $num"
                continue
        fi

        echo "number $num: delete $candidate"
        # remove the followong comment sign if you want the script to remove the file
        # rm $candidate
done

Answer 2

to fix the problem with spaces in filenames change setting of 'IFS' shell variable before the for-loop:

#! /bin/bash

myPath="/tmp"

myFileList=$(find $myPath -maxdepth 1   -type f  -printf "%T@ %p\n" |sort -rn|awk '1 {$1=""; print $0;}')

num=0

OIFS="$IFS"
IFS=$'\n'

for candidate in $myFileList
do
        num=$(($num + 1))

        if [[ $num -le 5 ]]
        then
                echo "do not delete: $num  \"$candidate\""
                continue
        fi

        echo "number $num: delete $candidate"
        # remove the followong comment sign if you want the script to remove the file
        # rm $candidate
done
IFS="$OIFS"