从 SQL 中的 Json 数组中提取所有值

Question

I have SQL-data, with one column of JSON-data. Unfortunately, my database only compatibility level 100. So I can't use OPENJSON() .

My JSON-data are structured as follows, it contains results from testing. I also have the columns id , model and type .

[
{ "name": "rtc", "value": "pass" }, 
{ "name": "battery", "value": "pass" }, 
{ "name": "connection", "value": "pass" }, 
{ "name": "timer", "value": "pass" }, 
{ "name": "provide", "value": "pass" }, 
{ "name": "request", "value": "fail" }
]

How do I get columns for rtc , battery , connection , timer , provide and request with cells that are pass / fail ?

Some products have all tests, while some only have a few.

I have tried JSON_Value(details, '$.name') , but that gives me null.

EDIT Expected output table, Either of the works:

Answer 1

If your SQL Server version supports JSON, you may try to parse the stored JSON data and pivot the rows:

Sample data:

DECLARE @json nvarchar(max) = N'[
{ "name": "rtc", "value": "pass" }, 
{ "name": "battery", "value": "pass" }, 
{ "name": "connection", "value": "pass" }, 
{ "name": "timer", "value": "pass" }, 
{ "name": "provide", "value": "pass" }, 
{ "name": "request", "value": "fail" }
]'
SELECT *
INTO Data
FROM (VALUES (1, @json)) v (id, details)

Statement:

SELECT *
FROM (
   SELECT d.id, j.[name], j.[value]
   FROM Data d
   CROSS APPLY OPENJSON(d.details) WITH (
      [name] nvarchar(50) '$.name',
      [value] nvarchar(4) '$.value'
   ) j
) t
PIVOT (
   MAX([value]) FOR [name] IN ([rtc], [battery], [connection], [timer], [provide], [request])
) p

Result:

id	rtc	battery	connection	timer	provide	request
1	pass	pass	pass	pass	pass	fail

Note, that you may get the unpivoted values with the following statement:

SELECT d.id, j.[name], j.[value]
FROM Data d
CROSS APPLY OPENJSON(d.details) WITH (
   [name] nvarchar(50) '$.name',
   [value] nvarchar(4) '$.value'
) j