[英]How to change tick-marks for y-axis in base histogram?
I would like to change my Y axis of these histograms to start at 20 and end at 180 AND making it so there is always 20 between each number (20, 40, 80,...).我想将这些直方图的 Y 轴更改为从 20 开始并以 180 结束,并使其在每个数字(20、40、80、...)之间始终存在 20。 How should I do it?
我该怎么做?
I read about yaxis command, but I just dont know how to make it work as I am a total noob in coding (no education in that area).我阅读了有关 yaxis 命令的信息,但我只是不知道如何使它工作,因为我是编码方面的菜鸟(在该领域没有受过教育)。
This is the graph I am working on:这是我正在处理的图表:
And this is the code I have:这是我的代码:
orientation$head_linear <- ifelse(orientation$head > 180, 360 - orientation$head, orientation$head) orientation$body_linear <- ifelse(orientation$body > 180, 360 - orientation$body, orientation$body) par(mfrow = c(2,1)) hist(orientation$head_linear, main = NULL, ylim=c(20,180), ylab = NULL, xlab = NULL) hist(orientation$body_linear, main = NULL, ylim=c(20, 180), ylab = NULL, xlab = " Odchylka od vletového otvoru ")
I have set the limit of Y axis with ylim code, but it doesnt seem to work (I have succesfully used it before in different work).我已经用 ylim 代码设置了 Y 轴的限制,但它似乎不起作用(我之前在不同的工作中成功使用过它)。
Maybe you mean the xaxt=
argument whith which you can omit the y-axis.也许您的意思是
xaxt=
参数,您可以省略 y 轴。 If you use it, you may create a custom axis
afterwards.如果你使用它,你可以在之后创建一个自定义
axis
。 Use a seq(from=0, to=360, by=20)
for it's at=
argument.使用
seq(from=0, to=360, by=20)
作为at=
参数。
par(mfrow=c(2, 1)) hist(orientation$head_linear, main=NULL, yaxt='n', ylab=NULL, xlab=NULL) axis(side=2, at=seq(from=0, to=360, by=20)) hist(orientation$body_linear, main=NULL, yaxt='n', ylab=NULL, xlab=" Odchylka od vletového otvoru ") axis(2, seq(0, 360, 20))
Data:数据:
n <- 500 orientation <- data.frame( head_linear=sample(360, n, replace=TRUE), body_linear=sample(360, n, replace=TRUE) )
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