从 Python shell 脚本打开 VSCode

Question

I'm trying to make a C++ project manager with Python in Ubuntu 22.04.

I'm trying to open VSCode from python using the following lines:

subprocess.run(["cd", project_dir], shell=True)
subprocess.run([utility.get_ide_cmd()], shell=True)

This runs without error, but does not open VSCode.
utility.get_ide_cmd() returns 'code .'

project_dir is the directory we want to open.

I'm running the python script by calling it from a bash script with python3 <name> <args> .

How do I open VSCode this way?

Answer 1

Kind of dumb of me.

Because Subprocess is its own shell, using cd then code in another shell is worthless. Using code project_dir works.

Thanks to @Charles Duffy