[英]Open a Python script from another Python script in another shell
I am working currently on Raspbian. 我目前正在研究Raspbian。 My Problem is i have a Python scrip with a infinite Loop that never should stop.
我的问题是我有一个带有无限循环的Python脚本,永远不要停止。 In This script i want to call another script without the main script stopping.
在此脚本中,我想在不停止主脚本的情况下调用另一个脚本。 I tried different methodes to do this like:
我尝试了不同的方法来做到这一点,例如:
import test1
test1.some_func()
or 要么
execfile("test1.py")
or 要么
import subprocess
subprocess.call("python test1.py")
I could start the test1.py script with these solutions, but the script that called it would stop working. 我可以使用这些解决方案启动test1.py脚本,但是调用该脚本的脚本将停止工作。 So my question is how to start a second script without the first one to stop.
所以我的问题是如何在不停止第一个脚本的情况下启动第二个脚本。
subprocess.call
waits for the command to complete and thus blocks your loop. subprocess.call
等待命令完成,从而阻塞了循环。 You should use something like process = subprocess.Popen(["python", "test1.py"])
. 您应该使用类似
process = subprocess.Popen(["python", "test1.py"])
。 If you want to wait for the process to terminate, you can then call process.wait()
. 如果要等待进程终止,则可以调用
process.wait()
。
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