如何使用javascript合并数组中的对象

Question

I want to merge objects present in an array.

INPUT:

[
   { 
     "email": "abc@gmail.com",
     "date": "2020-01-24",
     "name": "bc",
     "details": [{id:"1"}] 
   }, 
   { 
     "email": "xyz@abc.in",
     "date": "2020-01-22",
     "name": "de",
     "details": [{id:"1"}] 
   },
   { 
     "email": "efg@gmail.com",
     "details": [{id:2}]
   },
   { 
     "name": "ab",
     "email": "abc@gmail.com",
     "details": [{"id":"3"}] 
   },
   { 
     "name": "",
     "email": "xyz@abc.in",
     "age": "", 
     "details": [{id:"4"}]
   },
   { 
     "name": "ef",
     "email": "xyz@abc.in",
     "age": "",
     "details":[{id:"4"}]
   },
   { 
     "name": "",
     "email": "xyz@abc.in",
     "age":"18",
     "details":[{id:"4"}]
   } 
]

I want to merge based on email regex column(if I don't know the name of the field ie, it can be email or mail or any other name)

(i)if "id" inside details is same and email is matching then need to do row merge ie, if any field in the first row is empty then copy it from 2nd or 3rd row to 1st row and now delete dupicate rows with same "id".

(ii)If "id" inside details is different and email is same merge different objects into single object.

Kindly help me in finding the solution.

In (ii) condition while merging columns with different id's need to get all the merged id's inside details array.

EXPECTED OUTPUT

[
   {
     "email":"abc@gmail.com",
     "date": "2017-01-24",   
     "name": "bc",
     "age":"19",
     "details":[
                 {id:"1"},
                 {id:"3"}
                ]
   },
   { 
     "email": "xyz@abc.in",
     "date": "2017-01-22",  
     "name" :"ef",
     "age":"",
     "details": [
                  {id:1},
                  {id:4}
                ]
   },
   { 
     "email": "efg@gmail.com",
     "date": "",
     "name": "",
     "age": "",
     "details": [
                  {id:2}
                ]
   }
]

Answer 1

based on the list you've given this could be your solution.

(i)By looping over the inputList and checking if the (n) index exists in the newList it creates a new List without recurring emails.

(ii)When the email is known it'll check if the id matches (is findable) in the newItem (newItem is the item in newList with the where the email matches the (n) index of the inputList) if it's found it'll continues. If not it adds the item to the detail list.

 const list = [ { email: "abc@gmail.com", date: "2020-01-24", name: "bc", details: [{ id: "1" }], }, { email: "xyz@abc.in", date: "2020-01-22", name: "de", details: [{ id: "1" }], }, { email: "efg@gmail.com", details: [{ id: 2 }], }, { name: "ab", email: "abc@gmail.com", details: [{ id: "3" }], }, { name: "", email: "xyz@abc.in", age: "", details: [{ id: "4" }], }, { name: "ef", email: "xyz@abc.in", age: "", details: [{ id: "4" }], }, { name: "", email: "xyz@abc.in", age: "18", details: [{ id: "4" }], }, ]; const mergeList = (list) => { let newList = []; list.forEach((item) => { let isExist = false; newList.forEach((newItem) => { if (item.email === newItem.email) { isExist = true; if (!newItem.details.find((detail) => detail.id === item.details[0].id)) newItem.details.push(item.details[0]); return; } }); if (!isExist) { newList.push(item); } }); return newList; }; console.log(mergeList(list));

const mergeList = (list) => {
  let newList = [];
  list.forEach((item) => {
    let isExist = false;
    newList.forEach((newItem) => {
      if (item.email === newItem.email) {
        isExist = true;
        if (!newItem.details.find((detail) => detail.id === item.details[0].id))
          newItem.details.push(item.details[0]);
      }
    });
    if (!isExist) {
      newList.push(item);
    }
  });
  return newList;
};


  [1]: https://jsfiddle.net/wcd7t93g/2/