如何在 curl 中打印响应和状态码的第一行
[英]How to print first line of the response and status code in curl
问题描述
curl -o /dev/null -s -w "HTTPCode=%{http_code}_TotalTime%{time_total}s\n" http://test.com
just gives me the status code
只是给我状态码
I also want the body of the response, How can i do that in the command?我还想要响应的正文，我该如何在命令中做到这一点？
2 个解决方案
解决方案1
1 2022-08-01 15:36:32
Don't send it to /dev/null?不要将它发送到/dev/null？ -o is throwing it away. -o正在扔掉它。
curl -sw "HTTPCode=%{http_code}_TotalTime%{time_total}s\n" http://test.com
If you ONLY want the first line, as your title suggests, filter it.如果您只想要第一行，如您的标题所示，请过滤它。
curl -sw "HTTPCode=%{http_code}_TotalTime%{time_total}s\n" http://test.com | sed -n '1p; $p;'
This tells sed to print the first and last lines, because you asked for the first one, and -w prints after completetion.这告诉 sed 打印第一行和最后一行，因为您要求第一行，并且-w在完成后打印。 My test:我的测试：
$: curl -s -w "HTTPCode=%{http_code}_TotalTime%{time_total}s\n" google.com | sed -n '1p; $p;'
<HTML><HEAD><meta http-equiv="content-type" content="text/html;charset=utf-8">
HTTPCode=301_TotalTime0.270267s
If you specifically mean the first line of the body from the response, now you need to define "first line" a little, and you should really get an HTML-aware parser.如果您特别指的是响应中正文的第一行，那么现在您需要稍微定义“第一行”，并且您应该真正获得一个支持 HTML 的解析器。 I could probably do it in sed , but it's really kind of a bad idea in most cases.我可能可以在sed中做到这一点，但在大多数情况下这确实是个坏主意。
If that's really what you need, let me know, supply some additional details, and we'll work on it.如果这确实是您需要的，请告诉我，提供一些额外的细节，我们会努力解决的。
解决方案2
1 2022-08-01 17:03:47
You can use this curl + awk solution:您可以使用此curl + awk解决方案：
curl -sw "HTTPCode=%{http_code}_TotalTime%{time_total}s\n" 'http://test.com' |
awk '{p=p $0 ORS} END{print; sub(/\n[^\n]+\n$/, "", p); print p}'
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