将列的所有不同值添加到数组

Question

I'm trying to output the distinct values of a column into an array instead of SELECT DISTINCT column FROM table which would output 1 row per unique value. I am wanting to have just 1 row. I have tried a few method to do this but I keep ending up with the error:

syntax error: no viable alternative at input 'ARRAY_DISTINCT(SELECT' .

SELECT
    ARRAY_DISTINCT(SELECT column_1 FROM table WHERE p = '2022-08-17') as column_distinct_values

'Where `p` is the partition

I have also tried the below method which yields the same error.

SELECT
    ARRAY(SELECT DISTINCT column_1 FROM table WHERE p = '2022-08-17') as column_distinct_values

'Where `p` is the partition

So the question is, what is the correct syntax/method to achieve this?

---

Sample input/desired output

Answer 1

SELECT column_1 FROM table WHERE p = '2022-08-17' does not return an array, if you want to compact everything into one cell you can try group by with aggregation into array:

-- sample data
WITH dataset (val) AS (
    VALUES ('NORAM'),
    ('NORAM'),
    ('NORAM1')
)

-- query
select array_distinct(array_agg(val))
from dataset
group by true; -- fake grouping

Or

-- query
select array_agg(distinct val) 
from dataset 
group by true; -- fake grouping

Output:

_col0
[NORAM, NORAM1]