yq append 多个文件进入列表 yaml

Question

Assume I have a file root.yml

keyA: valA
keyB: valB
myList:

Then I receive some yml file, such as

1.yml

project_id: abc
description: xyz

2.yml

project_id: cba
description: zyx

And so on (they may stored in same folder)

Now I want to append the content of 1.yml , 2.yml (and so on) to the myList of root.yml and output to console

Expected:

keyA: valA
keyB: valB
myList:
  - project_id: abc
    description: xyz
  - project_id: cba
    description: zyx
  - (so on...)

I have searched some examples but they hard code the list item in the yq command, like this post: Stack Overflow

But I want it load from files, not from hard code Please forgive for my bad english

Answer 1

With mikefarah/yq , you could use the load function with the filename of the YAML files to be included, ie with your example

yq '.myList += [ load("1.yaml"), load("2.yaml") ]' root.yml

producing a YAML result as

keyA: valA
keyB: valB
myList:
  - project_id: abc
    description: xyz
  - project_id: cba
    description: zyx

As indicated in your comment , if one of the object has a parent structure and you want to extract the element from it, you can do

yq 'load("1.yaml") as $f | .myList += [ $f.config[], load("2.yaml") ]' root.yml

Tested on yq version 4.27.2