从 Python 中的 websockets 队列获取最新消息

Question

How do you get the last message received from server even if there are unread messages in queue?

Also, how could I ignore (delete) the rest of the unread messages?

CODE example:

while True:
    msg = await ws_server.recv()
    do_something_with_latest_message(msg)

I Nead something like:

while True:
    msg = await ws_server.recv_last_msg() # On next loop I should "await" until a newer msg comes, not te receive the previous msg in LIFO order
    do_something_with_latest_message(msg)

Answer 1

There's no way to do this natively, just with the websockets library. However, you could use an asyncio.LifoQueue :

queue = asyncio.LifoQueue()

async def producer(ws_server):
    async for msg in ws_server:
        await queue.put(msg)

async def consumer():
    while True:
        msg = await queue.get()
        # clear queue
        while not queue.empty():
            await queue.get()
        await do_something_with_latest_message(msg)
await asyncio.gather(producer(ws_server), consumer())