从 Python 中的 websockets 队列获取最新消息

Question

即使队列中有未读消息，如何获取从服务器收到的最后一条消息？

另外，我怎么能忽略（删除）未读邮件的 rest？

代码示例：

while True:
    msg = await ws_server.recv()
    do_something_with_latest_message(msg)

我需要类似的东西：

while True:
    msg = await ws_server.recv_last_msg() # On next loop I should "await" until a newer msg comes, not te receive the previous msg in LIFO order
    do_something_with_latest_message(msg)

Answer 1

仅使用websockets库就无法在本地执行此操作。 但是，您可以使用asyncio.LifoQueue ：

queue = asyncio.LifoQueue()

async def producer(ws_server):
    async for msg in ws_server:
        await queue.put(msg)

async def consumer():
    while True:
        msg = await queue.get()
        # clear queue
        while not queue.empty():
            await queue.get()
        await do_something_with_latest_message(msg)
await asyncio.gather(producer(ws_server), consumer())